| 代码: |
| select case when a.cnt = b.cnt then '两个库结构一致' when a.cnt <> b.cnt then '两个库结构不一致' end from (select count(*) as cnt from dba_tab_columns t1, dba_tab_columns@lnk_db2 t2 where t1.owner = 'TAOBAO' and t1.owner = t2.owner and t1.table_name = t2.table_name and t1.column_name = t2.column_name and t1.data_type = t2.data_type and t1.data_length = t2.data_length and t1.nullable = t2.nullable and nvl(t1.data_precision, 0) = nvl(t2.data_precision, 0) and nvl(t1.data_scale, 0) = nvl(t2.data_scale, 0)) a, (select count(*) as cnt from dba_tab_columns where owner = 'TAOBAO') b |
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